1N salt solution surrounding two platinum electrodes, 2.1 cm apart and 6.3 `cm^(2)` in area was found to offer a resistance of 50 ohm. Calculate the equivalent conductance of the solution.

0.5 N solution of an electrolyte placed between two platinum electrodes 2.0 cm apart and area of cross section 4.0 sq. cm has a resistance of 250 ohm . Calculate the equivalent conductance of the solution.

A 0.1N solution of NaCl has a specific conductance of 0.00112 ohm^-1 cm^-1 . Calculate the equivalent conductance of the solution.

The resistance of N//5 solution of an electrolyte in a cell was found to be 45 ohm. Calculate the equivalent conductance of the solution if the electrodes in a cell are 2.2 cm apart and have an area of 3.8 equiv. cm.

Define and explain specific conductance and equivalent conductance. Why on dilution the specific conductance decreases and equivalent conductance increases? A 0.1 N solution of sodium acetate has a specific conductance 0.0061 "ohm"^(-1)cm^(-1) . Calculate the equivalent conductance of the solution.

The specific conductance of a 0.12N solution of an electrolyte is 2.4xx10^-2 ohm^-1cm^-1 Calculate its equivalent conductance.