Home
Class 12
CHEMISTRY
Calculate the half-cell potential at 298...

Calculate the half-cell potential at 298 K for the reaction `Cu^(2+) ( aq) + 2e^(-) rarr Cu(s)` where `[ Cu^(2+) ]` is 5.0 M and `E^(@)` is `+` 0.34 V

Text Solution

Verified by Experts

The correct Answer is:
0.360V
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( MULTPILE CHOICE TYPE QUESTIONS) |5 Videos

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( VERY SHORT ANSWER TYPE QUESTIONS) |7 Videos

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise ODISHA BUREAU.S TEXTBOOK SOLUTIONS (SHORT ANSWER TYPE II QUESTIONS)|12 Videos

  • D-BLOCK ELEMENTS

    ARIHANT PUBLICATION|Exercise Chapter practice (Long answer type questions)|2 Videos

  • ELEMENTS : NITROGEN FAMILY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( Long Answer Type Questions ) |11 Videos

Similar Questions

Explore conceptually related problems

Calculate the half cell potential at 25^@C for the cell reaction Cu^(2+)(aq)+2erarrCu , When [Cu^(2+)]=4M and E^@(Cu^(2+)//Cu)=0.34V .

Write the Nernst equation for the electrode reaction: Cu_(aq)^(2+) + 2e rarr Cu(s)

The reaction, Cu^(2+)(aq) +2CI^- (aq) rarr Cu(s) +CI_2(g) has E_(cell)^@=1.03V .This reaction :

Calculate the value of equilibrium constant for the reaction at 298 k. Cu(s) +2Ag^+(aq)rarrCu^(2+)(aq)+2Ag(s) E^@ (Ag2+/Ag) =0.80V and E^@( Cu2+/Cu ) =0.34V

Complete the chemical reaction. Cu_2S + Cu_2O rarr

The equilibrium constant for the reaction Cu_(s) + 2Ag^+ _ (aq) rarr Cu^2+ _ (aq) +2Ag at 298 k is Given E^@cell=0.46v

What is meant by electrode potential? Explain in the half cell reactions of Zn(s) + Cu^(2+) ( aq) rarr Zn^(2+) (aq) + Cu(s)

Represent the galvanic cell in which the reaction, Zn(s) + Cu^(2+) (aq) rarr Zn^(2+) (aq) + Cu(s) take place.

ARIHANT PUBLICATION-ELECTROCHEMISTRY-ODISHA BUREAU.S TEXTBOOK SOLUTIONS (LONG ANSWER TYPE QUESTIONS)
  1. Write two applications of electrochemical series.

    Text Solution

    |

  2. A current of 0.5 amperes was passed through a solution of silver nitra...

    Text Solution

    |

  3. The resistance of N//5 solution of an electrolyte in a cell was found ...

    Text Solution

    |

  4. State and explain Faraday's laws of electrolysis. 0.2015g of copper we...

    Text Solution

    |

  5. Describe the construction and working of Daniell cell.

    Text Solution

    |

  6. Describe the construction and working of Daniell cell. The followin...

    Text Solution

    |

  7. What are the difference between ionisation and electrolysis? What are ...

    Text Solution

    |

  8. Differentiate between emf and potential difference.

    Text Solution

    |

  9. Write two applications of electrolysis.

    Text Solution

    |

  10. Define equivalent and molar conductance. Give their relationship with...

    Text Solution

    |

  11. State and explain equivalent conductance and specific conductance. Cal...

    Text Solution

    |

  12. Define and explain specific conductance and equivalent conductance. Wh...

    Text Solution

    |

  13. Calculate the half-cell potential at 298 K for the reaction Cu^(2+) ( ...

    Text Solution

    |

  14. State and explain Faraday's laws of electrolysis. 0.2015g of copper we...

    Text Solution

    |

  15. Define equivalent and molar conductance. Give their relationship with...

    Text Solution

    |

  16. State and explain equivalent conductance and specific conductance. Cal...

    Text Solution

    |

  17. State and explain Faraday's law of electrolysis. When a current of 1.5...

    Text Solution

    |

  18. Describe specific and equivalent conductance. How are they related? Wh...

    Text Solution

    |

  19. Define and explain specific conductance and equivalent conductance. ...

    Text Solution

    |

  20. State and explain Faraday's laws of electrolysis. How many grams of ch...

    Text Solution

    |