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The emf of a cell corresponding to the r...

The emf of a cell corresponding to the reaction, `Zn(s) + 2H^(+) ( aq) rarr Zn^(2+) ( 0.1 M ) + H_(2) ( g , 1 atm)` is 0.28 V at `25^(@)C`.
Write the half-cell reaction and calculate the pH of the solution at the hydrogen electrode.
`E_(Zn^(2+)//Zn)^(@) = - 0.76V, E_(H^(+) //H_(2))^(@) = 0 `

Text Solution

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The correct Answer is:
pH =8.6
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