Home
Class 12
CHEMISTRY
Calculate the equilibrium constant for t...

Calculate the equilibrium constant for the reaction. `2Fe^(2+) + 3I^(-) hArr 2Fe^(3+) + I_(3)^(-)`
The standard reduction potential in acidic condition is 0.78 V and 0.54 V , respectively . For `Fe^(3+) //Fe^(2+)` and `I_(3)^(-) //I` couples.

Text Solution

Verified by Experts

The correct Answer is:
`K_(eq) = 10^(8)`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( SHORT ANSWER TYPE II QUESTIONS) |8 Videos
  • D-BLOCK ELEMENTS

    ARIHANT PUBLICATION|Exercise Chapter practice (Long answer type questions)|2 Videos
  • ELEMENTS : NITROGEN FAMILY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( Long Answer Type Questions ) |11 Videos

Similar Questions

Explore conceptually related problems

Calculate the equilibrium constant for the reaction. Fe(s) + Cd^(2+) (aq) hArr Fe^(2+)(aq) + Cd(s) [ Given, E_(Cd^(2+) //Cd)^(@) = - 0.40V , E_(Fe^(2+)//Fe)^(@) = - 0.44 V ]

Is the reaction, 2Al +3Fe^(2+)rarr2Al^(3+) +3Fe possible?

Standard oxidation potential of iron electrode is + 0.44V. Calculate the potential of Fe, FeSO_(4) ( 1M ) at 25^(@)C .

The standard reduction potential for Fe^(2+) | Fe and Sn^(2+) | Sn electrodes are -0.44V and -0.14V respectively. For the cell reaction, Fe^(2+)+Sn rarr Fe +Sn^(2+) , the standard emf is :