Home
Class 12
CHEMISTRY
The rate constant for a first order reac...

The rate constant for a first order reaction is `60" s"^(-1)`. How much time will it take to reduce the initial concentration of the reactant to its 1/16th value?

Text Solution

Verified by Experts

The correct Answer is:
t = 0.0384
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER 4

    ARIHANT PUBLICATION|Exercise GROUP B |24 Videos
  • SAMPLE PAPER 1

    ARIHANT PUBLICATION|Exercise GROUP C|14 Videos
  • SAMPLE PAPER 5

    ARIHANT PUBLICATION|Exercise GROUP C |7 Videos

Similar Questions

Explore conceptually related problems

The rate constant for a first order reaction is 60" s"^(-1) . How much time will it take to reduce the concentration of the reactant of 1/10 th of its initial value?

The rate constant of a first order reaction is 0.60" sec"^(-1) . What is its half-life period?

For a 1st order reaction t_(1/2)=2 min. How long will it take to reach 25% of the initial conc. of the reactant ?

The rate for a first order reaction is 0.6932 xx 10^(-2)mol L^(-1) min^-1 and the initial concentration of the reactant is 1 M, t_(1//2) is equal to: