A Proton and an electron are placed 1.6 cm apart in free space. Find the magnitude and nature of electrostatic force between them.

Explanation

Charge on electron `= - 1.6 xx 10 ^(-19) C `
Charge on proton ` = 1.6 xx 10 ^(-19) C `
Using Coulomb.s law
` F = ( q_1q_2)/(4piin _0r^(2))`
Where ,r is the distance between proton and electron
` " " = ( 9 xx 10 ^(9) xx (1.6 xx 10 ^(-19)) (-1.6 xx 10 ^(-19)))/((1.6 xx 10 ^(-2))^(2))`
` =- 9 xx 10^(-25) N`
Negative sign indicates that the force is attractive in nature.