Two charges ` + 1mu C and +5 mu C ` are placed 0.1 cm aprt . What is the ratio of the Coulomb force acting on each of the two charges?

Explanation

Given `q_1 = + mu C ,q_2 = + 5 mu C , r = 0.1 cm =10 ^(-3) m `
` F_(12) : F_(21) = ? `
Since, ` " " F_(12) = (1 xx 5 xx 10 ^(-12))/(10 ^(-6)) xx 9 xx 10 ^(9) `
` = 4.5 xx 10 ^(4) N`
` " " F_(12) = (1 xx 5 xx 10 ^(-12))/(10 ^(-6)) xx 9 xx 10 ^(9) `
` = 4.5 xx 10 ^(4) N" " ` ( repulsive force )
` F_(21) = (5 xx 1 xx 10 ^(-12))/(10^(-6)) xx 9 xx 10 ^(9)`
` " " = 4.5 xx 10 ^(4)N" " `(repulsive force )
So , ` " " (F_(12))/(F_(21)) = (4.5 xx 10 ^(4))/(4.5 xx 10 ^(4)) =1: 1 `