Two identical metallic spheres, having unequal opposite charges are placed at a distance of 0.50 m apart in air. After bringing them in ir contact with each other, they are placed at the same distance apart. Now, the force of repulsion between them is 0.108 N. Calculate the final charge on each of them.

Explanation

Electrostatic force between spheres,
` " " F = (kq_1q_2)/(r^(2)) `
Here, ` " " F = 0.108 = (9 xx 10 ^(9) xx q^(2))/((0.5)^(2))`
` rArr " " q^(2) = 3 xx 10 ^(-12)`
` rArr " " q= sqrt3 muC `