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An electric field of 10^(5) N/S points d...

An electric field of `10^(5)` N/S points due west at a certain spot. What are the magnitude and direction of the force that acts on a charge of `+2muC` and `-5muC` at this spot ?

Text Solution

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`:.` Electrostactic force, `F=qE`
Force on `+2muC=qE`
where, E is the electric field of magnitude `10^(5)` N/C
`=(2xx10^(-6))(10^(5))=0.2N` (due west)
Force on `-5muC=(-5xx10^(-6))(10^(5))=-0.5N` (due west)
`=0.5` N (due east)
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