Calculate the magnitude of an electric field which can just suspend a deuteron of mass `3.2xx10^(-27)` kg freely in air.

Explanation

Upward force on the deuteron due to electric field qE is equal to weight mg of deuteron `qE=mg`
`:.E=(mg)/(q)=(3.2xx10^(-27)xx9.8)/(1.6xx10^(-19))=19.6xx10^(-8)"NC"^(-1)`