Electric Field Due to an Electric Dipole Two charges `pm5muC` are placed 5 mm apart. Determine the electric field at
a point Y, 10 cm away from centre O on line passing through O and normal to the axis of the dipole as shown in Fig. (b)

Explanation

Given, `q=pmCpm5xx10^(-6)C`
`2l=5" mm "=5xx10^(-3)m`
`x=OX=OY=10" cm "=10xx10^(-2)`m,
`E_(X)=?` and `E_(Y)=?`
`:.` Dipole moment,
`p=qxx2l=5xx10^(-6)Cxx5xx10^(-3)m`
`=25xx10^(-9)" C-m"`
Now, find out the electric field at point Y on equatorial line of dipole.
`E_(Y)=(p)/(4piepsilon_(0)(x^(2)+l^(2))^(3//2.))` along a line parallel to BA
Since, `l ltltx`, therefore `E_(Y)=(p)/(4pi epsilon_(0)x^(3))`
`:." "E_(Y)=(25xx10^(-9)xx9xx10^(9))/((10xx10^(-2))^(3))`
`=2.25xx10^(5)"NC"^(-1)`, along a line parallel to BA