Realation between Electric Field at potential
A small particla carrying a negative charge of `1.6xx10^(-19)C` is suspended in equilibrium between the horizontal metal plates 5 cm apart, having a potential difference of 3000 V across them. Find the mass of the particle.

Explanation

Here, `q=-1.6xx10^(-19)C," dr "=5cm=5xx10^(-2)m`,
`dV=3000` V,m=?
`:." "E=-(dV)/(dr)=(-3000)/(5xx10^(-2))=-6xx10^(4)" Vm"^(-1)`
As,the charged particle remains suspended in equilibrium, therefore
`F=mg=qE`
or `m=(qE)/(g)=((-1.6xx10^(-19))xx(-6xx10^(4)))/(9.8)`
`9.8xx10^(-16)kg`