The distance between a proton and electron both having a charge `1.6xx10^(-19)C` of a hydrogen atom is `10^(-10)m`. The value of intensity of electric field on electron due to proton will be

Options

A. `2.304xx10^(-10)` N/C
B. `14.4` V/m
C. 16 V/m
D. `1.44xx10^(11)` N/C

Explanation

`:.E=(q)/(4piepsilon_(0)r^(2))=9xx10^(9)xx(1.6xx10^(-19))/((10^(-10))^(2))=1.44xx10^(11)` N/C