Find the electric field intensity in which a proton experiences a force equal to its own weight. (Take, `m_(p)= 1.67 xx 10^(-27)kg, e^(-) = 1.6 xx 10^(-19)C`)

Explanation

Given, mass of proton, `m_(p)=1.67xx10^(-27)kg`
Charge on proton, `q_(p)=1.6xx10^(-19)C`
`g=10m//s^(2),E=?`
`:." "E=(F)/(q)=(m_(p)g)/(q)" "(F=m_(p)g)`
`=(1.67xx10^(-27))/(1.6xx10^(-19))xx10`
`E=1.04xx10^(-7)" V/m"`