Two point charges `q_(A)=3muC` and `q_(B)=-3muC` are located 20 cm apart in vacuum.
If a negative test charge of magnitude `1.5xx10^(-9)C` is placed at this point, then what is the force experienced by the test charge ?
Force on a charge in an electric field, `F=qE`.

Explanation

Let us consider, the charge q be placed at te mid - point O. According to the question,

By the basic definition of electric field, `E=(F)/(q)` or `F=qE`, where E is the net electric field at point O
`F=1.5xx10^(-9)xx5.4xx10^(6)=8.1xx10^(-3)N`
The direction of force of O to A.