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Eight dipole of charge of magnitude e ar...

Eight dipole of charge of magnitude e are placed inside a cube. The total electric flux coming out of the cube will be

A

`(8e)/(epsilon_(0))`

B

`(16e)/(epsilon_(0))`

C

`(e)/(epsilon_(0))`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
`phi=(Sigmaq)/(epsilon_(0))=0`, i.e. net charge on dipole is zero.
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