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A charge Q is the centre of circular pat...

A charge Q is the centre of circular path of radius R. Another charge q is taken around the circumference of circular path once. The work done will be

A

`(Qqr)/(2epsi_(0)R^(2))`

B

`Qq(r)/(R^(2))`

C

zero

D

`(Qqr^(2))/(R)`

Text Solution

Verified by Experts

The correct Answer is:
C
Zero, since the circumference of a circular path around a charge Q is an equipotential surface. So, the work done will be zero.
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