In SI unit, V at a point in an electric field is given by `V= -(6)/(x)+2`. Find the value of E in the field at the point (2, 0,0).

Explanation

Given, `V=-(6)/(x)+2`
`:.|E|=|-(dV)/(dx)|\=|-((-6)/(x^(2))+0)|rArrE=(6)/(x^(2))`
Given point is (2,0,0), i.e. `x=2` units.
So, `E=(6)/(2^(2))=1.5` units