Two charges `2muC` and `-2muC` are placed at points A and B, 6 cm apart.
What is the direction of the electric field at every point on this surface ?

Explanation

According to the formula, `E*dr=dV`, the value of dV=0 at each point of equipotential surface.
`:." "E*dr=0`
So, the angle between electric field vector and distance vector will be `90^(@)`. Thus the electric field is always normal to the plane passing through AB.