A test charge q is moved without acceleration from A to C along the path from A to B and then from B to C in electric field E as shown in the figure.

Calculate the potential difference between A and C.

Explanation

`because` Electric field intensity and potential difference are related as
`E=-(DeltaV)/(Deltar)rArr DeltaV=-E Delta r`
`:.V_(A)-V_(C)=-4E` or `V_(C)-V_(A)=4E" "(because" by Pythagoras law",AC^(2)=AB^(2)+BC^(2))`
`:." "5^(2)-3^(2)=AB^(2)` or `AB=Deltar=4`