When `1 xx 10^(12)` electrons are transferred from one conductor to another , a potential difference of 10 V appears between the conductors . Find the capacitance of the two conductors .

Explanation

Given , number of electrons,
`n = 1 xx 10^(12) , v = 10 V `
`:.` Charge transferred,
`Q = n e = 1 xx 10^(12) xx 1 . 6 xx 10 ^(-19)`
` = 1. 6 xx 10^(-7) C " "` [` :. e = 1 . 6 xx 10 ^(-19) C` ]
`:.` Capacitance between two conductors,
`C = (Q)/(V) = (1 . 6 xx 10 ^(-7))/( 10)`
` = 1 . 6 xx 10 ^(-8)` F `