The capacitors each of capacitance 9 pF are connected in series
What is the total capacitance of the combination

Explanation

There are three capacitors each of capacitance 9 pF
`:. C_(1) = C_(2) = C_(3) = 9 pF`
and voltage, V = 120 V
The total capacitance in series combination,
`(1)/(C_(s)) = (1)/(C_(1)) + (1)/( C_(2)) + (1)/( C_(3)) = (1)/(9) + (1)/(9) + (1)/(9) `
`(1)/(C_(s))= (3)/( 9) rArr C_(s) = 3 pF`