A metallic wire of length Im and diameter 1mm has a resistance of 2 `omega` . Calculate the resistance of a wire of same material and length having a diameter of 2 mm.

Explanation

Given the wires are of same material and length
So resistance `R prop (1)/(A)`
`therefore (R_(1))/(R_(2))=(A_(2))/(A_(1))=(d_(2))/(d_(1))`
`=2xx1/2= 1 omega`