Find the total charge carried by the number of free electrons in a copper wire of length 1 m and cross-section 1.6 `mm^(2)` if density of copper is `9xx 10^(@) kg//m^(3)` and its molecular mass 63.5 g `"mole"^(-1)`. Assume valency of copper to be one.

Explanation

Number of moles of copper
`=(m)/(M)=(9xx10^(3) xx1 xx1.6 xx10^(-6) xx10^(3) )/(63.5 xx10^(23))=(9xx1.6 xx10^(3))/(63.5)`
`therefore` charge `q="ne" =(29xx9xx1.6 )/(63.5)xx1.6xx10^(-19)xxN_(A)`
`=2.1854 xx10^(4) C`