The horizontal component of earth's field at a given place is `0.4 xx 10^(-4) Wb//m^(2)` and angle of dip is 30°. Calculate the value of
(i) verticalcomponent and (ii) total intensity of Earth's magnetic field.

Explanation

(i) `tan delta = B_(V)/B_(H)`
`tan 30^(@) = B_(V)/(0.4 xx 10^(-4)) rArr B_(V) = 0.23 xx 10^(-4) Wb//m^(2)`
(ii) `B = sqrt(B_(V)^(2)+ B_(H)^(2))`
`= sqrt((0.23 xx 10^(-4))^(2) + (0.4 xx 10^(-4))^(2))`
`=0.46 xx 10^(-4) Wb//m^(2)`