A horizontal straight wire `10` m long extending from East to West is falling with a speed of `5.0` m/s, at right angles to the horizontal component of the earth's magnetic field, `0.30xx10^(-4) Wb//m^(2)`.
(i) What is the intantaneous value of the emf induced in thr wire?
(ii) What is the direction of the emf ?
(iii) Which end of the wire is at the higher electrical potential ?

Explanation

Given velocity of straight wire, `v=5` m/s
Horizontal component of the earth.s magnetic field,
`B=0.30xx10^(4) Wb//m^(2)`
Length of wire, `l=10` m
(i) The emf induced in the wire, `e=Blvsintheta`
Here, `theta=90^(@)`
`:.sintheta=1` ( `:.` wire is falling at right angle to the earth.s horizontal magnetic field component)
`e=0.30xx10^(-4)xx10xx5xx1.5xx10^(-3)` V
(ii) According to the Fleming.s right hand rule, if the force is downward, then the direction of induced emf will be form West to East.
(iii) As, the direction of induced emfis from West to East, the West end of the wire is at higher potential.