An alternating current is given by `I = I_(1) cos omega t + I_(2) sin omega t`. Determine the rms value of current through the circuit.

Explanation

As, `I_(rms_(1)) = (I_(1))/(sqrt(2))`
and `I_(rms_(2)) = (I_(2))/(sqrt(2))`
Hence, the resultant of these two currents,
`I_(rms) = sqrt(((I_(1))/(sqrt(2)))^(2) + ((I_(2))/(sqrt(2)))^(2)) = sqrt((I_(1)^(2) + I_(2)^(2))/(2))`