An L-C-R series circuit is under resonance. If `I_(m)` is current amplitude, `V_(m)` is voltage amplitude, R is the resistance, Z is the impedance, `X_(L)` is the inductive reactance and `X_(C)` is the capacitive reactance, then

Options

A. `I_(m) = (V_(m))/(Z)`
B. `I_(m) = (V_(m))/(X_(L))`
C. `I_(m) = (V_(m))/(X_(C))`
D. `I_(m) = (V_(m))/(R)`

Answer

A