Half-life of a radioactive sample is 2 h. What fraction of sample will decay in 8 h?

Explanation

Using, `N = N_0(1/2)^n`
We get , `N = (N_0)/(2^n) = (N_0)/(2^4) = (N_0)/(16)` (`because` 8 h cover 4 half-lives)
`therefore`Decayed sample = `N_0 - N = 15/16 N_0`
`implies ` Fraction decayed of sample = `(N_0 - N)/(N_0) = 15/16`