Calculate the enthalpy of formation of methanol from the following data,
`CH_(3)OH(l) + (3)/(2)O_(2)(g) rarr CO_(2)(g) + 2H_(2)O(l) ….(i) " "Delta H^(@) = -726.4 kJ mol^(-1)`
`C"(graphite)" + O_(2)(g) rarr CO_(2)(g) ….(iii) " "Delta H^(@) = -393.5 kJ mol^(-1)`
`H_(2)(g) + (1)/(2)O_(2)(g) rarr H_(2)O(l) ....(iii) " "Delta H^(@) = -285.8 kJ mol^(-1)`.

Calculate the hest of reaction of the following reaction : C_(6)H_(12)O_(6(s)) + rarr 6CO_(2(g)) + 6H_(2)O_((g)) : Delta H = ?

On the basis of thermochemical equation (a), (b) and (c ), which of the algebric relationship is correct. ( a) C("graphite") + O_(2)(g) rarr CO_(2)(g) , Delta_(r)H = x kJ mol^(-1) (b) C("graphite") + (1)/(2)O_(2)(g) rarr CO(g) , Delta_(r)H = y kJ mol^(-1) ( c) CO(g) + (1)/(2)O_(2)(g) rarr CO_(2)(g) , Delta_(r)H = z kJ mol^(-1)

Calculate the enthalpy of formation of methane from the following data. C_((s))+O_(2_((g)))toCO_(2)(g)DeltaH^(@)=-393.5kJ …………..1 H_(2_((g)))+1/2O_(2(g))toH_(2)O_((l))DeltaH^(@)=-285.8kJ …………2 CH_(4_((g)))+2O_(2_((g))) rarr CO_(2)(g)+2H_(2)O_((l))DeltaH^(@)=-890kJ ......................3

Calculate the heat of reaction of the following reaction : CO_(2)(g) + H_(2)(g) rarr CO(g) + H_(2)O(g) Given that the Delta_(f)H^(@) of CO(g) = -110.5 kJ, Delta_(f)H^(@) of CO_(2)(g) = -393.8 kJ , Delta_(f)H^(@) of H_(2)O(g) = -241.8 kJ respectively

With the help of a thermochemical equation, calculate Delta_(f)H^(@) at 298 K for the following reactions : "C(graphite)" + O_(2)(g) rarr CO_(2)(g) , Delta H = -393.5 kJ//mol H_(2)(g) + (1)/(2)O_(2)(g) rarr H_(2)O(l) , Delta_(f)H^(@) = -285.8 kJ//mol CO_(2)(g) + 2H_(2)O(l) rarr CH_(4)(g) + 2O_(2)(g) , Delta_(f)H^(@) = +890.3 kJ//mol

Consider the following reaction : (A) H^(+)(aq) + OH^(-)(aq) = H_(2)O(l): Delta H = -X_(1) kJ mol^(-1) (B) H_(2)(g) + (1)/(2) O_(2)(g) = H_(2)O(l): Delta H = -X_(2) kJ mol^(-1) ( C ) CO_(2)(g) + H_(2)(g) = CO(g) + H_(2)O(l): Delta H = -X_(3) kJ mol^(-1) (D) C_(2)H_(2)(g) + (5)/(2) O_(2)(g) = 2CO_(2) + H_(2)O(l): Delta H = +X_(4) kJ mol^(-1) Enthalpy of formation of H_(2)O(l) is :

For the reaction, C_(2) H_(4) (g) + 3O(2) (g) to 2 CO_(2) (g) + 2H_(2) O(I), Delta E = -1415 KJ. then Delta H at 27^(@) C is

For the reaction : C_(3)H_(8)(g) + 5O_(2) rarr 3CO_(2)(g) + 4H_(2)O(l) a constant temperature, Delta H - Delta U is