On dissolving 2.34g of non-electrolyte solute in 40g of benzene, the boiling point of solution was higher than benzene by 0.81K. Kb value for benzene is 2.53 K `kgmol^(-1)` .Calculate the molar mass of solute. [Molar mass of benzene is 78 `gmol^(-1)`]

On dissolving 3.24 g of sulphur in 40 g of benzene,the boiling point of the solution was higher than that of benzene by 0.81K .What is the molecular formula of sulphur? ( K_(b) for benzene = 2.53 K kg mol^(-1) , atomic mass of sulphur = 32 g mol^(-1) ).

Vapour pressure of benzene is 200 mm of Hg. When 2 gram of a non-volatile solute dissolved in 78 gram benzene, benzene has vapour pressure of 195 mm of Hg. Calculate the molar mass of the solute. [Molar mass of benzene is 78 g/ mol^(-1) ]

0.90g of a non-electrolyte was dissolved in 90 g of benzene. This raised the boiling point of benzene by 0.25^(@)C . If the molecular mass of the non-electrolyte is 100.0 g mol^(-1) , calculate the molar elevation constant for benzene.

1.0 g of non - electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.4 K. Find the molar mass of the solute. [Given : Freezing point depression constant of benzene = 5.12 K. kg mol].

The boiling point of benzene is 353.23 K when 1.80 g of a non-volatile, non-ionising solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of solute. " " [Given K_(b) for benzene = 2.53 K kg mol^(-1) ]

The boiling point of benzene is 353.23 K . When 1.80 g of a non-volatile solute was dissolved in 90 g benzene, the boiling point is raised to 354.11 K . Calculate the molar mass of the solute. ( K_(b) for benzene is 2.53 K kg mol^(-1) )