In a region, an electric field `vec(E )= 5 xx 10^(3) hat(j) NC^(-1)` and a magnetic field of `vec(B)= 0.1 hat(K)T` are applied. A beam of charged particles are projected along X-direction. Find the velocity of charged particles which move an deflected in this crossed fields.

Explanation

Velocity =`v=(E )/(B)`
`v=(5xx10^(3))/(0.1)=5xx10^(4) ms^(-1)`
Detailed answer:
Charged particles move undeflected in crossed electric and magnetic field ,v=velocity
e=charge of the charged particles.
`v=(E )/(B)`
`v=5xx10^(3)//0.1`
`=5xx10^(4)ms^(-1)`