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Obtain an expression for the force betwe...

Obtain an expression for the force between two straight parallel conductor carrying current. Hence define ampere.

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The magnetic field at the location of .b. produced by the conductor .a. is `B_(a)=(mu_(0)I_(a))/(2pid)`……..(1)
The magnetic force on a segment L of the conductor .b. due to .a. is `F_(ba)=B_(a)l_(b)L` sin `90^(@)`
Using eq.(1),`F_(ba)=(mu_(0)I_(a)I_(b)L)/(2pid)` .This force `F_(ba)` is towards conductor .a..
Similarly ,we can find the magnetic force `F_(ab)` on segment L of the conductor .a. due to .be.
the force `F_(ab)` is equal in magnitude to `F_(ba)` ,and directed towards .b. .Thus `barF_(ba)=-barF_(ab)`
Definition of ampere:One ampere is that steady current which,when maintained in each of the two very long,straight ,parallel conductors of negligible cross-section and placed on metre apart on vacuum (free space),would produce a force of `2xx10^(-7)` newton per metre of length on each other.
(Note:Any other equivalent correct defination with required key terms shoulds be considered)
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