Home
Class 11
PHYSICS
The acceleration due to gravity at a hei...

The acceleration due to gravity at a height `1/20^(th)` of the radius of the earth above the earth surface is 9 `ms^(- 2)` . Its value at a point at an equal distance below the surface of the earth in `ms^(-2)` is about

A

8.5

B

9.3

C

9.8

D

11.5

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • FRICTION IS SOLIDS AND LIQUIDS

    TARGET PUBLICATION|Exercise MCQ (EVALUATION TEST)|21 Videos
  • LAWS OF MOTION

    TARGET PUBLICATION|Exercise EXERCISE|281 Videos

Similar Questions

Explore conceptually related problems

The acceleration due to gravity at a height (1//20)^(th) the radius of the earth above earth s surface is 9m//s^(2) Find out its approximate value at a point at an equal distance below the surface of the earth .

Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth

The acceleration due to gravity on the surface of earth varies

The acceleration due to gravity at a height 1km above the earth is the same as at a depth d below the surface of earth. Then :

Find the acceleration due to gravity at a distance of 20000 km from the centre of the earth.

The acceleration due to gravity at a given point on the earth is same for all the objects

Calculate the value of acceleration due to gravity at a point a. 5.0 km above the earth's surface and b. 5.0 km below the earth's surface. Radius of earth =6400 km and the value of g at the surface of the earth is 9.80 ms^2

The value of the acceleration due to gravity g on earth depends upon

The acceleration due to gravity is g at a point distant r from the centre of earth of radius R . If r lt R , then

Show that acceleration due to gravity at height h above the Earth’s surface is g_h = g ((R )/(R+h))^2

TARGET PUBLICATION-Gravitation-Exercise
  1. The value of 'g' at a depth of 80 km will be (Radius of earth=6400 km ...

    Text Solution

    |

  2. Consider earth to be a homogeneous sphere. Scientist A goes deep down ...

    Text Solution

    |

  3. The acceleration due to gravity at a height 1/20^(th) of the radius of...

    Text Solution

    |

  4. lf change in the value of g at a depth d below the surface of the eart...

    Text Solution

    |

  5. lf the earth of radius R, while rotating with angular velocity ro beco...

    Text Solution

    |

  6. R is the radius of the earth and omega is its angular velocity and gP ...

    Text Solution

    |

  7. What should be the angular speed of earth in radian/second so that a b...

    Text Solution

    |

  8. A body falls freely under gravity. Its speed is v when it has lost an ...

    Text Solution

    |

  9. The maximum vertical distance through which a full dressed astronaut c...

    Text Solution

    |

  10. A body of mass m rises to a height h = R/5 from the surface of the Ear...

    Text Solution

    |

  11. Me is the mass of earth and Mm is the mass of moon (Me=81 Mm). The pot...

    Text Solution

    |

  12. Ve and Vp denote the escape velocities from the earth and another plan...

    Text Solution

    |

  13. Escape velocity of a satellite of the earth at an altitude equal to ra...

    Text Solution

    |

  14. If the earth suddenly contracts so that its radius reduces by 4% with ...

    Text Solution

    |

  15. To have an earth satellite synchronous with the rotation of the earth,...

    Text Solution

    |

  16. The relay satellite transmits the T.V programme continously from one p...

    Text Solution

    |

  17. If a body is released from an artificial satellite then

    Text Solution

    |

  18. The orbital speed of Jupiter is

    Text Solution

    |

  19. The critical velocity of a satellite of mass l 00 kg is 20 km/hr. The ...

    Text Solution

    |

  20. The mean radius of the earth is R, its angular speed on its own axis i...

    Text Solution

    |