What should be the velocity of earth due...

What should be the velocity of earth due to rotation about its own axis so that the weight at equator becomes 3/5 of initial value? Radius of earth on equator is 6400 km

`7.4 xx 10^-4 rad/s`

`6.7 xx 10^-4 rad /s`

`7.9 xx 10^-4 rad/s`

`8.7 xx 10^-4 rad/s`

Text Solution

Verified by Experts

Topper's Solved these Questions

FRICTION IS SOLIDS AND LIQUIDS
TARGET PUBLICATION|Exercise MCQ (EVALUATION TEST)|21 Videos
LAWS OF MOTION
TARGET PUBLICATION|Exercise EXERCISE|281 Videos

Similar Questions

Explore conceptually related problems

What should be the velocity of earth due to rotation about its own axis so that the weight at equator become 3/5 of initial value. Radius of earth on equator is 6400 km

What should be the velocity of earth due to rotation about its own axis so that the weight at equator becomes 2/5 of initial value? Radius of earth on equator is 6400 km and is 10 m/s^2 .

Let omega be the angular velocity of the earth's rotation about its axis. Assume that the acceleration due to gravity on the earth's surface has the same value at the equator and the poles. An object weighed at the equator gives the same reading as a reading taken at a depth d below earth's surface at a pole (dlt ltR) . the value of d is-

What should be the velocity of sound from a source w.r.t. an observer, so that the frequency listened by the observer becomes half of the initial frequency?

If the value of the gravitational acceleration at the height h be 1% of its value at the surface of the earth, then h is equal to (given R_e=6400 km )

When a circular disc of radius 0.5 m is rotating about its own axis then the direction of its angular momentum is

What should be the angular speed of earth in radian/second so that a body of 5 kg weights zero at the equator? [Take g = 10 m//s^2 and radius of earth = 6400 km]

If omega_E and omega_H are the angular velocities of the earth rotating about its own axis and the hour hand of the clock respectively, then

Consider a spherical planet which is rotating about its axis such that the speed of a point on its equator is 'v' and the effective acceleration due to gravity on the equator is 1/3 of its value at the poles. What is the escape velocity for the particle at the pole of this planet?

Find the value of acceleration due to gravity in a mine at a depth of 80 km from the surface of the earth . Radius of the earth = 6400 km .

TARGET PUBLICATION-Gravitation-Exercise

The moon revolves around the earth in a circular orbit of radius - 3.8...
Text Solution
|
The ratio of the kinetic energy required to be given to the satellite ...
Text Solution
|
What should be the velocity of earth due to rotation about its own axi...
Text Solution
|
A light planet is revolving round a massive star with a period of revo...
Text Solution
|
Assertion: The artifical satellite does not have any fuel but even the...
Text Solution
|
Assertion: When an object is weighed with a physical balance, then its...
Text Solution
|
A satellite is placed in a circular orbit about Earth with radius equa...
Text Solution
|
A diametrical tunnel is dug across the Earth. A ball is dropped into t...
Text Solution
|
If the angular momentum of a planet of mass m, moving around the Sun i...
Text Solution
|
A planet is revolving around the sun as shown in the figure. The radiu...
Text Solution
|
The kinetic energies of a planet in an elliptical orbit about the Sun,...
Text Solution
|
Assume that the earth moves around the sun in a circular orbit of radi...
Text Solution
|
Two small satellites move in circular orbits arounds the earth respect...
Text Solution
|
A planet of mass m moves around the Sun along an elliptical path with ...
Text Solution
|
Two astronauts are floating in gravitational free space after having l...
Text Solution
|
Two particles of mass m(1) and m(2), approach each other due to their ...
Text Solution
|
A spherical planet far out in space has a mass M0 and diameter D0. A p...
Text Solution
|
Mass M is divided into two parts xm and (1 - x)m. For a given separati...
Text Solution
|
Four particles, each of mass M and equidistant from each other, move a...
Text Solution
|
Four identical particles of mass M are located at the corners of a squ...
Text Solution
|