Home
Class 11
PHYSICS
A body mass 'm' is dropped from height R...

A body mass 'm' is dropped from height `R/2`, from earth's surface, where 'R' is the radius of earth. Its speed when it will hit the earth's surface is (`v_e`= escape velocity from earth's surface)

A

`sqrt3 v_e`

B

`v_e/sqrt3`

C

`v_e/sqrt2`

D

`sqrt2 v_e`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • FRICTION IS SOLIDS AND LIQUIDS

    TARGET PUBLICATION|Exercise MCQ (EVALUATION TEST)|21 Videos

  • LAWS OF MOTION

    TARGET PUBLICATION|Exercise EXERCISE|281 Videos

Similar Questions

Explore conceptually related problems

A body of mass m rises to a height h=R//5 from the earth's surface where R is earth's radius. If g is acceleration due to gravity at the earth's surface, the increase in potential energy is

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is

A stone is dropped from a height equal to nR , where R is the radius of the earth, from the surface of the earth. The velocity of the stone on reaching the surface of the earth is

The height of a communication satellite from the earth's surface is about

A satellite orbiting close to earth surface will escape, if

If the earth suddenly contracts so that its radius reduces by 4% with mass remaining same, then what will happen to the escape velocity from earth's surface now?

A body of mass m is raised to a height 10 R from the surface of the earth, where R is the radius of the earth. Find the increase in potential energy. (G = universal constant of gravitational, M = mass of the earth and g= acceleration due to gravity)

Show that the escape velocity of a body from the surface of a planet of radius R and mean density rho is Rfrac(sqrt8pirhoG)(3) OR Show that the escape velocity of a body from the surface of the earth is 2Rfrac(sqrt2pirhoG)(3) , where R is the radius of the earth and rho is the mean density of the earth. OR Obtain formula of escape velocity of a body at rest on the earth's surface in terms of mean density of erth.

A body of mass m taken form the earth's surface to the height is equal to twice the radius (R) of the earth. The change in potential energy of body will be

Discuss the variation of g with depth and derive the necessary formula. OR Show that the gravitational acceleration due to the earth at a depth d from its surface is g_d= g[1- frac(d)(R)] , where R is the radius of the earth and g is the gravitional acceleration at the earth's surface. OR Discus the variation of acceleration due to gravity with depth 'd' below the surface of the earth OR Derive an expression for acceleration due to gravity at depth 'd' below the surface of earth

TARGET PUBLICATION-Gravitation-Exercise
  1. A satellite is revolving in a circular orbit at a height 'h' from the ...

    Text Solution

    |

  2. A satellite is revolving in a circular orbit at a height 'h' above the...

    Text Solution

    |

  3. A body mass 'm' is dropped from height R/2, from earth's surface, wher...

    Text Solution

    |

  4. The mass density of a spherical galaxy varies as K/r over a large dist...

    Text Solution

    |

  5. Consider a spherical planet which is rotating about its axis such that...

    Text Solution

    |

  6. Kepler's third law states that square of period of revolution (T) of a...

    Text Solution

    |

  7. A planet of mass 'm' moves in an elliptical orbit around an unknown st...

    Text Solution

    |

  8. The ratio of accelerations due to gravity g1 : g2 on the surfaces of t...

    Text Solution

    |

  9. A body is thrown from the surface of the earth with velocity 'u' mis. ...

    Text Solution

    |

  10. A particle of mass M is situated at the centre of a spherical shell of...

    Text Solution

    |

  11. A light planet is revolving round a massive star with a period of revo...

    Text Solution

    |

  12. At what height from the surface of earth the gravitation potential and...

    Text Solution

    |

  13. A satellite of mass 'm' is revolving in circular orbit of radius 'r' r...

    Text Solution

    |

  14. The radii of a planet and its satellite are 2r and r and their densiti...

    Text Solution

    |

  15. The radius of the Earth is about 6400 km and that of Mars is about 320...

    Text Solution

    |

  16. Given radius of Earth 'R' and length of a day 'T' the height of a geos...

    Text Solution

    |

  17. The mass of planet Jupiter is 1.9xx10^(27)kg and that of the Sun is 1....

    Text Solution

    |

  18. A mass M is broken into two parts of masses m1 and m2. How are m1 and ...

    Text Solution

    |

  19. Suppose the gravitational force varies inversely as the n^(th) power o...

    Text Solution

    |

  20. A body is projected vertically upwards from the surface of a planet of...

    Text Solution

    |