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Given radius of Earth 'R' and length of ...

Given radius of Earth 'R' and length of a day 'T' the height of a geostationary satellite is [G- Gravitational Constant, M-Mass of earth]

A

`((4pi^2 GM)/T^2)^(1/3)`

B

`((4pi GM)/R^2)^(1/3) -R`

C

`((GMT^2)/(4pi^2))^(1/3) -R`

D

`((GMT^2)/4 pi^2)^(1/3) +R`

Text Solution

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