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Let omega be the angular velocity of ear...

Let `omega` be the angular velocity of earth's rotation about the axis. Assume the acceleration due to gravity on the earth's surface has the same value at the equator and poles. An object weighed at the equator gives the same reading as a reading taken at a depth d below earth's surface at the pole (d ltlt R). The value of dis

A

`(omega^2 R^2)/g`

B

`(omega^2 R^2)/2g`

C

`(2omega^2 R^2)/g`

D

`(sqrt(Rg)/g`

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