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M' kg of water at 't' ^@C is divided int...

M' kg of water at 't' `^@C` is divided into two parts so that one part of mass 'm' kg when converted into ice `0^@C` would release enough heat to vapourise the other part, then `m/M` is equal to [Specific heat of water =` 1 calg^-1^@C^-1` Latent heat of fusion of ice=` 80 calg^-1` Latent heat of steam = `540 cal g^-1`]

A

`640-t`

B

`(720- t)/640`

C

`(640 + t)/720`

D

`(640 -t)/720`

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TARGET PUBLICATION-Thermal Properties of Matter-Exercise
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