Home
Class 11
PHYSICS
60 g of ice at 0^@C is mixed with 60 g o...

60 g of ice at `0^@C` is mixed with 60 g of steam at `100^@C`. At thermal equilibrium, the mixture contains (Latent heat of steam and ice are `540 g^-1` and `80 cal g^-1` respectively, specific heat of water = `1cal g^-1^@C^-1`)

A

80 g of water and 40 g of steam at`100^@C`

B

120 of water at`90^@C`

C

120 g of water at`100^@C`

D

40 g of steam and 80 g of water at`0^@C`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • Sound

    TARGET PUBLICATION|Exercise Exercise|248 Videos

Similar Questions

Explore conceptually related problems

1 gram of ice is mixed with 1 gram of steam. At thermal equilibrium, the temperature of the mixture is

1 of a steam at 100^@C melts how much ice at 0^@C ? ( Latent heat of ice=80 cal/g and latent heat of steam =540 cal/g )

The water equivalent of a calorimeter is 10 g and it contains 50 g of water at 15^@C . Some amount of ice, initially -10^@C is dropped in it and half of the ice melts till equilibrium is reached. What was the initial amount of ice that was dropped (when specific heat of ice = 0.5 cal g^-1^@C^-1, specific heat of water = 1.0 cal g^1^@C^-1 and latent heat of melting of ice =80 cal g^-1 )?

Steam at 100^@C is passed into 20 g of water at 10^@C When water acquires a temperature of 80^@C , the mass of water present will be Take specific heat of water= 1 cal g^-1^@ C^-1 and latent heat of steam = 540 cal g^-1 )

Complete the analogy: Latent heat of fusion of ice : 80 cal/g :: steam:

When 0.1 kg of ice at 0 ^@C is mixed with 0.32 kg of water at 35 ^@C in a container. The resulting temperature of the mixture is 7.8 ^@C . Calculate the heat of fusion of ice (S_water = 4186 J kg^-1 K^-1)

2 kg of ice at -20^@C is mixed with 5 kg of water at 20^@C in an insulating vessel having a negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific beats of water and ice are 1 (kcal)/(kg^@C) and 0.5 (kcal)/(kg^@C) while she latent heat of fusion of ice is 80 (kcal)/(kg)

A thermos flask contains 250 g of coffee at 90^@C . To this 20 g of milk at 5^@C is added. After equilibrium is established, the temperature of the liquid is (Assume no heat loss to the thermos bottle. Take specific heat of coffee and milk as 1.00 cal/(g^@C) )

Find the heat required to convert 20 g of ice at 0⁰C into water at the same temperature . (Specific latent heat of fusion of ice = 80 cal/g)

TARGET PUBLICATION-Thermal Properties of Matter-Exercise
  1. M' kg of water at 't' ^@C is divided into two parts so that one part o...

    Text Solution

    |

  2. 1 gram of ice is mixed with 1 gram of steam. At thermal equilibrium, t...

    Text Solution

    |

  3. 60 g of ice at 0^@C is mixed with 60 g of steam at 100^@C. At thermal ...

    Text Solution

    |

  4. Four rods with different radii and length l are used to connect two he...

    Text Solution

    |

  5. Two metal rods of same length and same material conduct a given amount...

    Text Solution

    |

  6. A cylindrical metallic rod in thermal contact with two reservoirs of h...

    Text Solution

    |

  7. The two ends of a metal rod are maintained temperatures 100^@C and 110...

    Text Solution

    |

  8. Two rectangular blocks, having identical dimensions can be arranged ei...

    Text Solution

    |

  9. Same quantity of ice is filled in each of the two metal containers P a...

    Text Solution

    |

  10. Three rods of copper, brass and steel are welded together to form a Y-...

    Text Solution

    |

  11. A refrigerator door is 150 cm high, 80 cm wide and 6 cm thick. If the ...

    Text Solution

    |

  12. Air conditioners are good example of

    Text Solution

    |

  13. The unit of thermal conductivity is:

    Text Solution

    |

  14. Two rods A and B of different materials are welded together shown in f...

    Text Solution

    |

  15. If a piece of metal is heated to temperature and then allowed to cool ...

    Text Solution

    |

  16. Newton's law of cooling leads to the expression

    Text Solution

    |

  17. A liquid in a beaker has temperature theta(t) at time t and theta0 is ...

    Text Solution

    |

  18. A liquid cools from 70^@C to 60^@C in 5 minutes. If the temperature of...

    Text Solution

    |

  19. A pan filled with hot food cools from 94^@C to 86^@C in 2 minutes. Wh...

    Text Solution

    |

  20. Certain quantity of water cools from 70^@C to 60^@C in the first 5 min...

    Text Solution

    |