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3[sin^4((3pi)/2-alpha)+sin^4(3pi+alpha)]...

`3[sin^4((3pi)/2-alpha)+sin^4(3pi+alpha)]-2[sin^6(pi/2+alpha)+sin^6(5pi-alpha)]=`

A

1) 0

B

2) 1

C

3) 3

D

4) `sin4alpha+sin6alpha`

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Knowledge Check

  • lim_(alpha to pi/4) (sin alpha -cos alpha)/(alpha -pi/4) =

    A
    `\sqrt{2}`
    B
    `1/\sqrt{2}`
    C
    1
    D
    None of these

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