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If tan20^@=lamda, then (tan160^@-tan110^...

If `tan20^@=lamda`, then `(tan160^@-tan110^@)/(1+(tan160^@)(tan110^@))=`

A

`(1+lamda^2)/(2lamda)`

B

`(1+lamda^2)/(lamda)`

C

`(1-lamda^2)/(lamda)`

D

`(1-lamda^2)/(2lamda)`

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