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If n =1,2,3,…, then cos alpha cos 2 al...

If `n =1,2,3,…,` then
`cos alpha cos 2 alpha cos 2^(2) alpha cos 2 ^(3) alpha. Cos 2 ^(n-1) alpha` equal to

A

1) `(sin2nalpha)/(2nsinalpha)`

B

2) `sin2^nalpha/(2^nsin2^(n-1)alpha)`

C

3) `sin4^(n-1)alpha/(4^(n-1)sinalpha)`

D

4) `sin2^(n)alpha/(2^(n)sinalpha)`

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