If frac{2z1}{3z2} is a purely imaginary...

If ` frac{2z_1}{3z_2}` is a purely imaginary number, then `abs(frac{z_1-z_2}{z_1+z_2}) = `

A

`frac{3}{2}`

B

1

C

`frac{2}{3}`

D

`frac{4}{9}`

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