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[frac{1+cosphi+isinphi}{1+cosphi-isinphi...

`[frac{1+cosphi+isinphi}{1+cosphi-isinphi}]^n = `

A

`cosnphi-isinphi`

B

`cosnphi+isinnphi`

C

`sinnphi+icosnphi`

D

`sinnphi-isinnphi`

Text Solution

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