If x+frac{1}{x} = 2costheta, then x is e...

If `x+frac{1}{x} = 2costheta`, then `x` is equal to

A

`A.costheta+isintheta`

B

`B.sintheta-isintheta`

C

`C.costheta pm isintheta`

D

`D.sintheta+icostheta`

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