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If a= e^(itheta), then frac{1+a}{1-a} ...

If ` a= e^(itheta)`, then `frac{1+a}{1-a} ` is equal to

A

`cot(frac{theta]{2})`

B

`tantheta`

C

`icot(frac{theta}{2})`

D

`itan(frac{theta}{2})`

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