If the cube roots of unity are 1,omega,(...

If the cube roots of unity are 1,`omega`,`(omega)^2`, then the roots of the equation `(x-2)^3+27 = 0` are

A

`A.-1,-1,-1`

B

`B.-1,-omega,-(omega)^2`

C

`C.-1,(2+3omega),(2+3(omega)^2)`

D

`D.-1,(2-3omega),(2-3(omega)^2)`

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