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which among the following pairs of ions ...

which among the following pairs of ions cannot be separated by `H_(2)S` in the presence of dilute `HCl` ?

A

`Bi^(3+) , Sn^(4+)`

B

`Al^(3+), Hg^(2+)`

C

`Zn^(2+), Cu^(2+)`

D

`Ni^(2+), Cu^(2+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which pair of ions cannot be separated by H₂S in the presence of dilute HCl, we need to analyze the solubility of the ions in the solution and whether they form precipitates when H₂S is added. ### Step-by-Step Solution: 1. **Understanding the Reaction**: - When H₂S is added to a solution containing metal ions, it can precipitate certain metal sulfides. The presence of dilute HCl will help maintain the ions in solution by preventing the precipitation of certain ions that are soluble in acidic conditions. 2. **Analyzing the Options**: - **Option A**: Bi³⁺ and Sn⁴⁺ - Both Bi³⁺ (bismuth) and Sn⁴⁺ (tin) can form precipitates with H₂S. Therefore, they will both precipitate and cannot be separated easily. - **Option B**: Al³⁺ and Hg₂²⁺ - Al³⁺ (aluminum) does not precipitate with H₂S, while Hg₂²⁺ (mercury) does. Thus, they can be separated easily since one remains in solution and the other precipitates. - **Option C**: Zn²⁺ and Cu²⁺ - Zn²⁺ (zinc) does not precipitate with H₂S, but Cu²⁺ (copper) does. Hence, they can also be separated easily. - **Option D**: Ni²⁺ and Cu²⁺ - Ni²⁺ (nickel) does not precipitate with H₂S, while Cu²⁺ (copper) does. Thus, they can be separated as well. 3. **Conclusion**: - The only pair of ions that cannot be separated by H₂S in the presence of dilute HCl is **Option A: Bi³⁺ and Sn⁴⁺**, as both will precipitate and remain together in the solution. ### Final Answer: **Option A: Bi³⁺ and Sn⁴⁺ cannot be separated by H₂S in the presence of dilute HCl.** ---
To determine which pair of ions cannot be separated by H₂S in the presence of dilute HCl, we need to analyze the solubility of the ions in the solution and whether they form precipitates when H₂S is added. ### Step-by-Step Solution: 1. **Understanding the Reaction**: - When H₂S is added to a solution containing metal ions, it can precipitate certain metal sulfides. The presence of dilute HCl will help maintain the ions in solution by preventing the precipitation of certain ions that are soluble in acidic conditions. 2. **Analyzing the Options**: ...
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