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A gas 'X' is passed through water to for...

A gas 'X' is passed through water to form a solution. The aqeous solution on treatment with `AgNO_(3)` solution gives a white precipitate. The sturated aqueous solution also dissolves magnesium ribbon with the evolution of colourless gas 'Y'. Identify 'X' and 'Y'

A

`X = CO_(2), Y = Cl_(2)`

B

`X = Cl_(2), Y = CO_(2)`

C

`X = Cl_(2), Y = H_(2)`

D

`X = H_(2), Y = Cl_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify the gas 'X' and the gas 'Y' based on the reactions described. Let's break it down step by step: ### Step 1: Identify the Reaction of Gas 'X' with Water - The problem states that gas 'X' is passed through water to form a solution. This implies that 'X' must be a gas that can dissolve in water and react to form an aqueous solution. ### Step 2: Analyze the Reaction with AgNO3 - The aqueous solution formed from gas 'X' is treated with AgNO3, resulting in a white precipitate. A common reaction that produces a white precipitate when treated with AgNO3 is the formation of silver chloride (AgCl). This suggests that the solution contains chloride ions (Cl⁻). ### Step 3: Determine the Identity of Gas 'X' - Since the solution contains chloride ions, we can infer that gas 'X' is likely chlorine gas (Cl2). When chlorine gas dissolves in water, it reacts to form hydrochloric acid (HCl) and hypochlorous acid (HOCl): \[ Cl_2 + H_2O \rightarrow HCl + HOCl \] - This reaction produces chloride ions in the solution, which would react with AgNO3 to form AgCl, the white precipitate. ### Step 4: Analyze the Reaction with Magnesium Ribbon - The problem states that the saturated aqueous solution also dissolves magnesium ribbon, producing a colorless gas 'Y'. The reaction of hydrochloric acid (HCl) with magnesium (Mg) is: \[ Mg + 2HCl \rightarrow MgCl_2 + H_2 \] - In this reaction, hydrogen gas (H2) is produced, which is colorless. ### Step 5: Conclusion - Based on the analysis: - Gas 'X' is chlorine (Cl2). - Gas 'Y' is hydrogen (H2). ### Final Answer - **X = Cl2 (Chlorine gas)** - **Y = H2 (Hydrogen gas)** ---
To solve the problem, we need to identify the gas 'X' and the gas 'Y' based on the reactions described. Let's break it down step by step: ### Step 1: Identify the Reaction of Gas 'X' with Water - The problem states that gas 'X' is passed through water to form a solution. This implies that 'X' must be a gas that can dissolve in water and react to form an aqueous solution. ### Step 2: Analyze the Reaction with AgNO3 - The aqueous solution formed from gas 'X' is treated with AgNO3, resulting in a white precipitate. A common reaction that produces a white precipitate when treated with AgNO3 is the formation of silver chloride (AgCl). This suggests that the solution contains chloride ions (Cl⁻). ...
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